2021-07-26 07:00发布 生成海报
not(strfind(stkname,'ST',1)>0) and c>=ref(c,1)*1.035
and any(cross(c,ma(c,5)) or cross(c,ma(c,6)),2)
and count(c>ref(c,1)*1.035,3)=1 and any(c 解锁全文需 1 财富值,免费注册即送20财富值!